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Q. A car is moving on a horizontal circular road of radius $0.1\, km$ with constant speed. If coefficient of friction between tyres of car and road is $0.4$, then speed of car may be $\left(g=10\, m / s ^{2}\right)$

Laws of Motion

Solution:

Maximum speed for the circular road
$\frac{v_{\text {maximum }}^{2}}{r} =\mu g$
$V_{\text {maximum }} =\sqrt{\mu r g}$
$=\sqrt{0.4 \times 100 \times 10}$
$=\sqrt{400}=20\, m / s$