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Q. A capacitor with air as the dielectric is charged to a potential of $100$ volts. If the space between the plates is now filled with a dielectric of dielectric constant $10$, the potential difference between the plates will be

Electrostatic Potential and Capacitance

Solution:

New potential difference $=\frac{V}{K}$
$=\frac{100}{10}=10\, V$