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  4. A capacitor of capacitance 50 μ F is charged to 10 volts. Its energy is equal to

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Q. A capacitor of capacitance $50\,\mu F$ is charged to $10\, volts$. Its energy is equal to

Electrostatic Potential and Capacitance

Solution:

$E = \frac{1}{2} CV^2 = \frac{1}{2} \times 50 \times 10^{-6} \times (10)^2 $ J = 2.5 $\times 10^3$ J.