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Physics
A capacitor is connected to a cell of emf E having some internal resistance r. The potential difference across the
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Q. A capacitor is connected to a cell of emf $E$ having some internal resistance $r$. The potential difference across the
Current Electricity
A
Cell is $ < E$
B
Cell is $E$
C
Capacitor is $ > E$
D
Capacitor is $ < E$
Solution:
In the given case, cell is in open circuit $(i=0)$ as capacitor reaches steady state, so voltage across the cell is equal to its e.m.f.