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Q. A capacitor $4\, \mu F$ charged to $50, V$ is connected to another capacitor of $2\, \mu F$ charged to $100\, V$ with plates of like charges connected together. The total energy before and after connection in multiples of $\left(10^{-2} J \right)$ is

Electrostatic Potential and Capacitance

Solution:

The total energy before connection
$=\frac{1}{2} \times 4 \times 10^{-6} \times(50)^{2}+\frac{1}{2} \times 2 \times 10^{-6} \times(100)^{2}$
$=1.5 \times 10^{-2} J$
When connected in parallel,
$4 \times 50+2 \times 100=6 \times V$
$\Rightarrow V=\frac{200}{3}$
Total energy after connection
$=\frac{1}{2} \times 6 \times 10^{-6} \times\left(\frac{200}{3}\right)^{2}$
$=1.33 \times 10^{-2} J$