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Q. A calorimeter of mass $0.2\, kg$ and specific heat $900\, J / kg - K$. Containing $0.5\, kg$ of a liquid of specific heat $2400\, J / kg - K$. Its temperature falls from $60^{\circ} C$ to $55^{\circ} C$ in one minute. Find the rate of cooling.

Thermal Properties of Matter

Solution:

Rate of cooling (here it is rate of loss of heat)
$\frac{d Q}{d t} =(m c +W) \frac{d \theta}{d t}$
$=\left(m_{l} c_{l}+m_{c} c_{c}\right) \frac{d \theta}{d t}$
$\Rightarrow \frac{d Q}{d t} =(0.5 \times 2400+0.2 \times 900)\left(\frac{60-55}{60}\right)$
$=115 \frac{ J }{ \sec} $