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Q. A bus turns a slippery road having coefficient of friction of $0.5$ with a speed of $10\, m / s$. The minimum radius of the arc in which bus turns is $\left[\right.$ Take $\left.g=10\, m / s ^{2}\right]$

Laws of Motion

Solution:

$\frac{v^{2}}{r}=\mu g$
$\frac{10 \times 10}{r}=0.5 \times 10$
$r=20\, m$