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Q. A bus travelling the first one third distance at a speed of $10 \,km/h$, the next one third at $20 \,km/h$ and the last one-third at $60 \,km/h$. The average speed (in km/h) of the bus is

Motion in a Straight Line

Solution:

Average speed $= \frac{s}{\frac{s/3}{10}+\frac{s/3}{20} +\frac{s/3}{6}} $
$= \frac{s}{s/18} = 18 km/h$