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Q. A bullet of mass $20\, g$ is moving with a speed of $150\, ms ^{-1}$. It strikes a target and is brought to rest after piercing $10\, cm$ into it. Calculate the average force of resistance offered by the target.

Work, Energy and Power

Solution:

Given, $m=20\, g =0.02\, kg , u=150\, ms ^{-1}, v=0$
and $s=10\, cm =0.1\, m$
According to the work-energy theorem, we have
$K-K^{\prime}=W=F s$
$\therefore \frac{1}{2} m u^{2}-0=F s$
$\Rightarrow F=\frac{m u^{2}}{2 s}=\frac{0.02 \times(150)^{2}}{2 \times 0.1}$
$=2250\, N$