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Q. A bullet of mass $10 \,g$ moving with a speed of $20\, m / s$ hits an ice block of mass $990\, g$ kept on a frictionless floor and gets stuck in it How much ice will melt if $50 \%$ of the lost KE goes to ice? (initial temperature of the ice block and bullet $=0^{\circ} C$ )

Thermal Properties of Matter

Solution:

$50 \%$ of lost KE goes to melt ice
$\Rightarrow \frac{1}{2} \times \frac{1}{2} \times \frac{10 \times 20 \times 20}{1000}=1 \,J$
Amount of ice that melts $=\frac{1}{80 \times 4.2}=0.003 \,g$