Question

A bullet is fired with a velocity u making an angle of $30^{\circ}$ with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is:

• A. $\frac{u}{\sqrt{2}}$
• B. $u$
• C. $u\sqrt{3}$
• D. $\frac{\sqrt{3}}{2}u$

Answer 1

Answer: (D)

Horizontal component of the velocity does not change in over all motion of projectile.
So, at highest point it will be.
$u$ cos $\theta = u$ cos $30^{\circ}$
$=\frac{u\sqrt{3}}{2}$