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Q. A buffer solution has equal volumes of $0.2M \, NH_4OH$ and $0.02\, M \, NH_4 Cl$. The $p^{kb}$ of the base is $5$. The $pH$ is

KCETKCET 2005Equilibrium

Solution:

$pOH = p K_{b}+\log \frac{[ salt ]}{[ base ]}$

(Henderson's equation)

$=5+\log \frac{0.02}{0.2}=5+\log \frac{1}{10}$

$=5+(-1)=4 $

$ pH =14- pOH =14-4=10 $