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Q. A buffer solution contains $0.1$ mole of sodium acetate dissolved in $1000 \,cm^3$ of $0.1\, M$ acetic acid. To the above buffer solution, $0.1$ mole of sodium acetate is further added and dissolved. The $pH$ of the resulting buffer is

KCETKCET 2011Equilibrium

Solution:

$pH = pK _{a}+\log \frac{[ salt ]}{\text { [acid] }}$

When extra $0.1$ mole sodium acetate is added

[salt] $=0.2\, mol\, dm ^{-3}$

[acid] $=0.1\, mol\, dm ^{-3}$

$\therefore PH = p K_{a}+\log \frac{[0.2]}{[0.1]}$

$pH = pK _{a}+\log 2$