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  4. A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 ms-2, the velocity with which it hits the ground is

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Q. A boy standing at the top of a tower of $20\,m$ height drops a stone. Assuming $g = 10\, ms^{-2},$ the velocity with which it hits the ground is

AIPMTAIPMT 2011Motion in a Straight Line

Solution:

Here, $u=0, g=10\, m s ^{-2}, h=20\, m$
Let $v$ be the velocity with which the stone hits the ground.
$\therefore v^{2}=u^{2}+2 g h$
or $v=\sqrt{2 g h}$
$=\sqrt{2 \times 10 \times 20}=20 \,m / s (\because u=0)$