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  4. A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2, the horizontal force that he is applying on the pole is

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Q. A boy of mass $40\, kg$ is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is $0.8$ and $g = 10 \,m/s^2$, the horizontal force that he is applying on the pole is

WBJEEWBJEE 2010Laws of Motion

Solution:

The coefficient of friction $=0.8,$
$ g=10\,m / s ^{2}$,
mass $=40 \,kg$
The frictional force $=\mu N$
Hence, $\mu N =m g$
$ \Rightarrow N=\frac{m g}{\mu} $
$= \frac{40 \times 10}{0.8}=500 \,N $