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  4. A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is . N.(Round off to the Nearest Integer) [Take g=10 ms -2 ] <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/c9f2306c1bb8c670d8bd799e2ecaa4a2-.png />

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Q. A boy of mass $4\,kg$ is standing on a piece of wood having mass $5\,kg$. If the coefficient of friction between the wood and the floor is $0.5$, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is _________. $N$.(Round off to the Nearest Integer) [Take $g=10\,ms ^{-2}$ ]
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JEE MainJEE Main 2021Laws of Motion

Solution:

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$N + T =90$
$T =\mu N =0.5(90- T )$
$1.5 T =45$
$T =30$