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Q. A boy of height $1.5 m$ with his eye level at $1.4 m$ stands before a plane mirror of length $0.75 m$ fixed on the wall. The height of the lower edge of the mirror above the floor is $0.8 m$. Then :

Ray Optics and Optical Instruments

Solution:

image
$\frac{ MP }{ PC }=\frac{ AB }{ BC } $
$ \therefore \frac{ MP }{2 x }=\frac{0.8}{ x }$
or $MP =1.6 m >1.4 m$
Hence, the boy cannot see his feet.