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Q.
A boy can throw a stone up to a maximum height of $10\,m$. The maximum horizontal distance that the boy can throw the same stone up to will be :
AIEEEAIEEE 2012Motion in a Plane
Solution:
For vertically projected up body maximum height $( H )$ is given as $H =\frac{ u ^2}{(2 g )}$
For the same bocy with same initial velocity the horizontal distance traveled when thrown at an $\operatorname{angle}(\theta)$ is given as
$
R =\frac{ u ^2}{ g } \text {. }
$
Compare equations 1 and 2
$
\begin{array}{l}
R =2 H \\
R =2 \times 10 \\
R =20 m
\end{array}
$