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Q. A boy $1.5 \,m$ tall with his eye level at $1.38\, m$ stands before a mirror fixed on a wall. The minimum length of mirror required to view the complete image of boy is

Ray Optics and Optical Instruments

Solution:

Let $A B$ represents the boy with height $A B=1.5 m$ and $C$ represents the eye level.
image
Let $M N$ represents the minimum height of the mirror.
$\Rightarrow M N=F C+C E$
$=\left(\frac{B C}{2}\right)+\left(\frac{A C}{2}\right)=0.06+0.69$
$\therefore MN =0.75\, m$