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  4. A box of mass m kg is placed on the rear side of an open truck accelerating at 4 ms-2 The coefficient of friction between the box and the surface below it is 0.4. The net acceleration of the box with respect to the truck is zero. The value of m is

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Q. A box of mass $m \,kg$ is placed on the rear side of an open truck accelerating at $4 \,ms^{-2}$ The coefficient of friction between the box and the surface below it is $0.4$. The net acceleration of the box with respect to the truck is zero. The value of $m$ is

Laws of Motion

Solution:

Pseudo force on the block
$=m \times 4\,N$ (backward)
Force of friction $=0.4 \times m \times 10\,N$ (forward)
Equating, $m \times 4 =0.4 \times m \times 10$
or $4\,m=4\,m$
Clearly the equation holds good for all values of $m$