1. Tardigrade
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  4. A box contains nine slips bearing the numbers -4,-3,-2,-1,0,1,2,3,4. A slip is drawn 9 times with replacement and the slip numbers noted, are arranged row wise to form a 3 × 3 matrix, starting from the first element of first row and continuing in this similar manner then, the probability that the matrix so formed is a skew-symmetric is equal to ((1/m))n then m-n is equal to

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Q. A box contains nine slips bearing the numbers $-4,-3,-2,-1,0,1,2,3,4$. A slip is drawn 9 times with replacement and the slip numbers noted, are arranged row wise to form a $3 \times 3$ matrix, starting from the first element of first row and continuing in this similar manner then, the probability that the matrix so formed is a skew-symmetric is equal to $\left(\frac{1}{m}\right)^n$ then $m-n$ is equal to

Probability

Solution:

Correct answer is '4'