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  4. A box contains 6 red marbles numbers from 1 through 6 and 4 white marbles 12 through 15. Find the probability that a marble drawn 'at random' is white and odd numbered.

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Q. A box contains $6$ red marbles numbers from $1$ through $6$ and $4$ white marbles $12$ through $15$. Find the probability that a marble drawn 'at random' is white and odd numbered.

KCETKCET 2015Probability

Solution:

Total number of marbles, $n(S)=6+4=10$
Marbles which are white and odd numbered $=2$
$\therefore n(E)=2$
Now, $ P(E)=\frac{n(E)}{n(S)}=\frac{2}{10}$
$=\frac{1}{5}$