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  4. A bomber flying upward at an angle of 53° with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g = 10 m s-2,the velocity at the time of release of the bomb in ms-1 is

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Q. A bomber flying upward at an angle of 53$^\circ$ with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g = 10 m s$^{-2}$,the velocity at the time of release of the bomb in $ms^{-1}$ is

Motion in a Plane

Solution:

-h - ut - $\frac{1}{2}$ g t$^2$