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Q. A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

NEETNEET 2020Gravitation

Solution:

$w_{s}=mg_{s}=72\,N$
$w_{h}=mg_{h}=\frac{mg_{s}}{\left(1+\frac{h}{R}\right)^{2}}$
$=\frac{72\,N}{\left(1+\frac{R /2}{2}\right)}$
$=\frac{72}{9 /4}$
$w_{h}=32\,N$