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  4. A body thrown vertically upwards with a speed of 19.6 ms -1 from the top of a tower returns to the earth in 10 seconds. What will be its height attained?

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Q. A body thrown vertically upwards with a speed of $19.6\, ms ^{-1}$ from the top of a tower returns to the earth in $10$ seconds. What will be its height attained?

Motion in a Straight Line

Solution:

Body covers equal distance in ascending or descending
$h = ut +\frac{1}{2} gt ^{2} \quad( u =- ve )$
$( g = +ve$ because after passing highest position motion is under gravity)
$ h =-19.6 \times 10+\frac{1}{2} \times 10 \times 100 \quad( g =+ ve ) $
$=-196+5 \times 100 $
$ =500-196 $
$ h =304 \,m$