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Q. A body takes 5 min to cool from $80^{\circ}\,C$ to $70^{\circ}\,C$. To cool From $80^{\circ}\,C$ to $60^{\circ}\,C$, it will take
(Room temperature = $40^{\circ}\,C$)

Odisha JEEOdisha JEE 2010Thermal Properties of Matter

Solution:

According to Newton's law of cooling
$\frac{\theta_1-\theta_2}{t}=K\left[\frac{\theta_1+\theta_2}{2}-\theta_0\right]$
$\therefore $ $\frac{80-70}{5}=K\left[\frac{80+60}{2}-40\right]$
$\Rightarrow K=\frac{2}{35}$
Again $\frac{80 - 60}{t}=\frac{2}{35}\left[\frac{80+60}{2}-40\right]$
$\approx 11.55\approx 12min$