Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body starts to fall freely under gravity. The distances covered by it in first, second and third seconds are in ratio

ManipalManipal 2011Motion in a Straight Line

Solution:

According to equation of motion, distance covered in $n$th $\sec$.
$S_{n} =u=\frac{a}{2}(2 n-1)$
$S_{n} =\frac{a}{2}(2 n-1)$
$\therefore S_{1}: S_{2}: S_{3}=\{2(1)-1\}:\{2(2)-1\}:\{2(3)-1\}$
$=1: 3: 5$