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  4. A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that coverd in 5 seconds is

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Q. A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the $5^{th}$ second to that coverd in 5 seconds is

Motion in a Straight Line

Solution:

Distance covered in $5^{th}$ second is
$D_{5} = 0+\frac{a}{2}\left(2\times5-1\right) = \frac{9a}{2}$
Distance covered in 5 seconds is
$S_{5} = 0+\frac{1}{2} \times a\times5^{2} = \frac{25a}{2}$
$\therefore \quad \frac{D_{5}}{S_{5}} = \frac{9}{25}$