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Q. A body rolls down an inclined plane without slipping. The kinetic energy of rotation is $50 \%$ of its translational kinetic energy. The body is :

JEE MainJEE Main 2021System of Particles and Rotational Motion

Solution:

$\frac{1}{2} I \omega^{2}=\frac{1}{2} \times \frac{1}{2} m v^{2}$
$I=\frac{1}{2} m R^{2}$
Body is solid cylinder