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  4. A body projected vertically upwards with a velocity u returns to the starting point in 4 s. If g = 10 m s-2, the value of u in m/s is

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Q. A body projected vertically upwards with a velocity u returns to the starting point in $4 s$. If $g = 10 \,m s^{-2}$, the value of $u$ in $m/s$ is

KCETKCET 1999Motion in a Straight Line

Solution:

Time of ascent = Time of descent = $\frac{4}{2} $ = 2 s
$\nu $ u + (-gt) i.e. 0 = u - 10 $\times$ 2 i.e. u = 20 m $s^{-1}$