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  4. A body of weight 72 N moves from the surface of earth at a height half of the radius of earth, then gravitational force exerted on it will be

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Q. A body of weight $72 \,N$ moves from the surface of earth at a height half of the radius of earth, then gravitational force exerted on it will be

AIPMTAIPMT 2000Gravitation

Solution:

$F_{\text {surface }}=G \frac{M m}{R_{e}^{2}}$
$F_{R_{e} / 2}=G \frac{M m}{\left(R_{e}+R_{e} / 2\right)^{2}}=\frac{4}{9} \times F_{\text {surface }}$
$=\frac{4}{9} \times 72=32\, N .$