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Q. A body of mass m is kept on a rough horizontal surface (coefficient of friction = m) A horizontal force is applied on the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by F, where F is :

NEETNEET 2019Laws of Motion

Solution:

$N = mg, F = f$
Resultant $=\sqrt{N^2 + f^2}$
$=\sqrt{(mg)^2 + f^2} \le mg\sqrt{1 + \mu^2}$