1. Tardigrade
  2. Question
  3. Physics
  4. A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body of mass $M$ hits normally a rigid wall with velocity $V$ and bounces back with the same velocity. The impulse experienced by the body is

BITSATBITSAT 2018

Solution:

A Body of mass $=m$
velocity $=V(\hat{i})$
Knock out (Bounce velocity) $=V(-\hat{i})$
Change in momentum $=m(v)-(m)(-v)$
$=2 M V$
Rate of change of momentum is Force
Thus $\frac{d \vec{p}}{d t}=$ force.
force $\times$ time $=$ Impulse
Thus Impulse Experience by body $=2 m v .$