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  4. A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J . The height at which the kinetic energy of the body becomes half of the original value is: (take g as 9.8 m s- 2 )

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Q. A body of mass $5 \, kg$ is thrown vertically up with a kinetic energy of $490 \, J$ . The height at which the kinetic energy of the body becomes half of the original value is : (take $g$ as $9.8 \, m \, s^{- 2}$ )

NTA AbhyasNTA Abhyas 2022

Solution:

According to the law of conservation of energy
$\frac{1}{2}mu^{2}=\frac{1}{2}mv^{2}+mgh$
$490=245+5\times 9.8\times h$
$h=\frac{245}{49}=5m$