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  4. A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. The magnitude of acceleration of the body is

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Q. A body of mass $5 \,kg$ is acted upon by two perpendicular forces $8\, N$ and $6 \,N$. The magnitude of acceleration of the body is

Laws of Motion

Solution:

$ F_{\text {net }}=\sqrt{8^{2}+6^{2}} N =10\, N$
$a=\frac{F_{\text {net }}}{M}=\frac{10 N }{5 kg }=2 \,m / s ^{2}$