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Q. A body of mass $4 kg$ is thrown upward with a velocity of $40 m / s$ it comes to rest after attaining maximum height of $30 m$. How much energy is lost due to air friction?

Work, Energy and Power

Solution:

Initial energy of body $K.E =\frac{1}{2} m v^{2}=\frac{1}{2} \times 4 \times 40 \times 40$
=3200 J
At highest point, energy possesses in the form of
potential energy $P . E$ mgh $=4 \times 10 \times 30=1200 J$
Energy lost due to air friction is
$\Delta E=E_{i}-E_{f}$
$\Delta E =3200-1200$
$\Delta E =2000 J$