Thank you for reporting, we will resolve it shortly
Q.
A body of mass $4.9\, kg$ hangs from a spring and oscillates with a period $0.5\, s$. On the removal of the body, the spring is shortened by (Take $ g=10\text{ m}{{s}^{-2}},{{n}^{2}}=10 $ )
Time period of oscillation, $T=2 \pi \sqrt{\frac{m}{k}}$ where $m$ is the mass of the body suspended from a spring and $k$ is spring constant of the spring.
or $k=\frac{4 \pi^{2} m}{T^{2}}$
Substituting the given values, we get
$
k=\frac{4 \times 10 \times 4.9}{(0.5)^{2}} Nm ^{-1}
$
On the removal of the body, the spring is shortened by $x$.
$
\therefore m g=k x
$
or $x=\frac{m g}{k}=\frac{4.9 \times 10 \times(0.5)^{2}}{4 \times 10 \times 4.9}$
(Using (i))
$
=\frac{0.25}{4}=0.0625 m =6.25 cm
$