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Q. A body of mass $3kg$ is moving under the action of a force such that its displacement is given by the relation $s=\frac{1}{3}t^{2}$ , where $t$ is time in second. The work done by the force in $2s$ is

NTA AbhyasNTA Abhyas 2022

Solution:

$s=\frac{1}{3}t^{2}$
$v=\frac{d s}{d t}=\frac{2}{3}t,a=\frac{d^{2} s}{d t^{2}}=\frac{2}{3}$
$F=ma=3\times \frac{2}{3}=2 \, N$
$W= \, 2\times \frac{1}{3}t^{2}$
At $t=2 \, s$ ,
$W=2\times \frac{1}{3}\times 2\times 2=\frac{8}{3} \, J$