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Q. A body of mass $2\, kg$ makes an elastic collision with another body at rest and continues to move in the original direction with one-fourth its original speed. The mass of the second body which collides with the first body is

ManipalManipal 2009Work, Energy and Power

Solution:

Conservation of linear momentum gives
$m_{1} u_{1} +m_{2} u_{2} =m_{1} v_{1}+m_{2} v_{2}$
$\Rightarrow m_{2} v_{2} =\frac{3 u}{2}$
Conservation of kinetic energy gives
$\frac{1}{2} m_{1} u_{1}^{2}+\frac{1}{2} m_{2} u_{2}^{2}$
$=\frac{1}{2} m_{1} v_{1}^{2}+\frac{1}{2} m_{2} v_{2}^{2}$
$\Rightarrow m_{2} v_{2}^{2}=\frac{15 u^{2}}{8}$
Hence, on solving Eqs. (i) and (ii), we get
$m_{2}=1.2\, kg$