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  4. A body of mass 2 kg is moving with a momentum of 10 kg ms-1. The force needed to increase its kinetic energy by four times in 10 seconds is

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Q. A body of mass $2 \,kg$ is moving with a momentum of $10 \,kg\, ms^{-1}$. The force needed to increase its kinetic energy by four times in $10$ seconds is

KEAMKEAM 2020

Solution:

$K E=\frac{P^{2}}{2 M}$
$\Rightarrow P$ momentum two times
$\Rightarrow \Delta P=P'-P=P=F \times t$
$10=F \times 10$
or $F=1 N$