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  4. A body of mass 2.4 kg is subjected to a force which varies with distance as shown in figure. The body starts from rest at x=0 . Its velocity at x=9 m is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/5b6673da423070ab7ab9f0a2c9bb01e1-.png />

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Q. A body of mass $2.4 \,kg$ is subjected to a force which varies with distance as shown in figure. The body starts from rest at $x=0 .$ Its velocity at $x=9 \,m$ is
image

TS EAMCET 2015

Solution:

Work done in a moving body is get converted into kinetic energy.
image
$\therefore \int F d x =\frac{1}{2} m\left(v^{2}-0^{2}\right) $
$ \Rightarrow \frac{1}{2}(9+3)(20) =\frac{1}{2}(2.4) v^{2} $
$ \Rightarrow v =10 \,m / s $