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Q. A body of mass $10\, kg$ initially at rest acquires velocity $10\, m/s$. What is the work done?

Delhi UMET/DPMTDelhi UMET/DPMT 2008

Solution:

By work-energy theorem
$W=\Delta K=\frac{1}{2} \times 10 \times(10)^{2}-0$
$=500\, J$