Question

A body of mass $1.0\, kg$ is rotating on a circular path of diameter $2.0\, m$ at the rate of $10$ rotations in $31.4\, s$. The angular momentum of the body, in $ kg-{{m}^{2}},s $ is

• A. 1.0
• B. 1.5
• C. 2.0
• D. 4.0

Answer 1

Answer: (C)

Angular momentum $L=m r^{2} \omega$
$=1 \times(1)^{2} \times 2 \pi n $
$=2 \pi n=\frac{2 \times 3.14 \times 10}{31.4}$
$=2 \,kg -m^{2} / s$