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Q. A body moves a distance of $10\, m$ under the action of force $F=10\, N$. If the work done is $25\, J$, the angle which the force makes with the direction of motion is

ManipalManipal 2019

Solution:

Work done, $W=F d \cos \theta$
$25=10 \times 10 \cos \theta$
$\cos \theta=\frac{1}{4}$
$\Rightarrow \theta=\cos ^{-1}\left(\frac{1}{4}\right)$