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  4. A body is under the action of two mutually perpendicular forces of 3 N and 4 N . The resultant force acting on the body is

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Q. A body is under the action of two mutually perpendicular forces of $ 3\,N $ and $ 4\,N $ . The resultant force acting on the body is

KEAMKEAM 2008Laws of Motion

Solution:

Resultant force, $F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \cos \theta}$
$=\sqrt{(3)^{2}+(4)^{2}+2 \times 3 \times 4 \cos 90^{\circ}}$
$=5\, N$