Thank you for reporting, we will resolve it shortly
Q.
A body is rolling without slipping on a horizontal surface and its rotational kinetic energy is equal to the translational kinetic energy. The body is
Rajasthan PETRajasthan PET 2004
Solution:
$ {{K}_{rot}}=K $ $ \frac{1}{2}I{{\omega }^{2}}=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}M{{R}^{2}}{{\omega }^{2}} $ $ I=M{{R}^{2}} $
Therefore, body is a ring.