Question

A body is projected with a speed 'u’ at an angle $'\theta'$ with the horizontal. The radius of curvature of the trajectory when it makes an angle $\left(\frac{\theta}{2} \right)$ with the horizontal is
(g - acceleration due to gravity)

• A. $\frac{u^{2} \cos^{2} \theta \sec^{3} \left( \theta/2\right)}{\sqrt{3}g}$
• B. $\frac{u^{2} \cos^{2} \theta \sec^{3} \left( \theta/2\right)}{2 g}$
• C. $\frac{ 2 u^{2} \cos^{2} \theta \sec^{3} \left( \theta/2\right)}{g}$
• D. $\frac{u^{2} \cos^{2} \theta \sec^{3} \left( \theta/2\right)}{g}$

Answer 1

Answer: (D)

Correct answer is (d) $\frac{u^{2} \cos^{2} \theta \sec^{3} \left( \theta/2\right)}{g}$