Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body is projected vertically upward with speed $10\, m / s$ and other at same time with same speed in downward direction from the top of a tower. The magnitude of acceleration of first body w.r.t second is $\left\{\right.$ take $\left.g=10\, m / s ^{2}\right\}$

Motion in a Straight Line

Solution:

The acceleration of first body
$a_{1}=10\, ms ^{-2}$
$a_{2}=10\, ms ^{-2}$
$a_{ rel }=a_{1}- a _{2}=10\, ms ^{-2}-10\, ms ^{-2}=0$