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Q. A body is projected horizontally with velocity $196\, m/s$ from height $400\, m$. What is the time to reach the ground?

Delhi UMET/DPMTDelhi UMET/DPMT 2008Motion in a Plane

Solution:

Time to reach the ground is given by
$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\times 400}{10}}$
$=4\sqrt{5} = 9\, s$