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  4. A body is projected horizontally from the top of a tower with a velocity of 10 m/s. If it hits the ground at an angle of 45°, then the vertical component of velocity when it hits ground (in m/s) is

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Q. A body is projected horizontally from the top of a tower with a velocity of $10\, m/s$. If it hits the ground at an angle of $45^{\circ}$, then the vertical component of velocity when it hits ground (in m/s) is

Motion in a Plane

Solution:

$\tan 45^{\circ}=\frac{V_{y}}{V_{x}}$
$1=\frac{V_{y}}{V_{x}}$
$V _{ y }= V _{ x } =10 m / s$
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